Question

4x^2+12x-9=9* ayudaaaa es examen

Answer 1

Respuesta:

$4x^{2} + 12x - 9 = 9\\4x^{2} + 12x - 9 - 9 = 9 -9\\4x^{2} + 12x - 18 = 0$     $4x^{2} + 12x - 18 = 0\\ax^{2} + bx + c = 0$

formula: $\frac{-b (+,-)\sqrt{b^{2} - 4ac }}{2a\\}$

$\frac{-12 + \sqrt{12^{2} - 4(4)(-18)}}{2(4)}\\\\\frac{-12 + \sqrt{144 - (-288)}}{8} \\\\\frac{-12 + \sqrt{144 + 288}}{8} \\\\\frac{-12 + \sqrt{432}}{8} \\\\\frac{-12 + 20.78}{8} \\\\\frac{8.78}{8}\\\\= 1.0975$   $\frac{-12 - \sqrt{12^{2} - 4(4)(-18)}}{2(4)}\\\\\frac{-12 - \sqrt{144 - (-288)}}{8} \\\\\frac{-12 - \sqrt{144 + 288}}{8} \\\\\frac{-12 - \sqrt{432}}{8} \\\\\frac{-12 - 20.78}{8} \\\\\frac{-32.78}{8}\\\\= -4.0975$