Question

hola me ayudan con esto porfavor.
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Answer 1

Respuesta:

A)

$5 \sqrt{x + 7} = 20 \\ \sqrt{x + 7} = 20 \div 5 \\ \sqrt{x + 7} {}^{2} = {4}^{2} \\ x + 7 = 16 \\ x = 16 - 7 \\ x = 9 \\ 5 \sqrt{9 + 7} = 20$

B)

$\sqrt[3]{3x + 1} = - 2 \\ 3x + 1 { = - 2}^{3} \\ 3x + 1 = - 8 \\ 3x = - 8 - 1 \\ 3x = - 9 \\ x = - 9 \div 3 \\ x = - 3$

C)

$\sqrt{3x + 1} \div 2 + 5 = 9 \\ \frac{1}{2} \times \sqrt{3x + 1} + 5 - 9 \\ \sqrt{3x + 1} + 10 = 18 \\ \sqrt{3x + 1} = 18 - 10 \\ \sqrt{3x + 1} = 8 \\ \sqrt{3x + 1 } {}^{2} = {8}^{2} \\ 3x + 1 = 64 \\ 3x = 64 - 1 = 63 \\ x = 63 \div 3 \\ x = 21$

D

$\sqrt[4]{4x + 41} + 2 = 5 \\ \sqrt[4]{4x + 41} = 5 - 2 \\ \sqrt[4]{4x + 41} {}^{4} = {3}^{4} \\ 4x + 41 = 81 \\ 4x = 81 - 41 \\ 4x = 40 \\ x = 40 \div 4 \\ x = 10$

E)

$10 = 3 \sqrt[3]{x + 3} + 4 \\ - 3 \sqrt[3]{x + 3} = 4 - 10 \\ - 3 \sqrt[3]{x + 3} = - 6 \\ - 3 \sqrt[3]{x + 3} \div ( - 3 )= - 6 \div ( - 3) \\ \sqrt[3]{x + 3 } = 2 \\ \sqrt[3]{x + 3} {}^{3} = {2}^{3} \\ x + 3 = 8 \\ x = 8 - 3 \\ x = 5$

F)

$9 - 2 \sqrt{x + 1} = 3 \\ - 2 \sqrt{x + 1} = 3 - 9 \\ - 2 \sqrt{x + 1} = - 6 \\ - 2\sqrt{x + 1} \div ( - 2) = - 6 \div ( - 2) \\ \sqrt{x + 1} = 3 \\ \sqrt{x + 1} ^{2} = {3}^{3} \\ x + 1 = 9 \\ x = 9 - 1 \\ x = 8$

Explicación paso a paso:

Espero que te ayude. Suerte