Question

Ayudaaaaaaaa por favor

Answer 1

Respuesta:

$(3 {x}^{3} - x)( - 2x) = - 6 {x}^{4} + 2 {x}^{2}$

$(8 {x}^{2} y - 3 {y}^{2} )(2a {x}^{3} ) = 16a {x}^{5} y - 6a {x}^{3} {y}^{2}$

$( {x}^{2} - 4x + 3)( - 2x) = - 2 {x}^{3} + 8 {x}^{2} - 6x$

$( {a}^{3} - 4 {a}^{2} + 6a)(3ab) = 3 {a}^{4} b - 12 {a}^{3} b + 18 {a}^{2} b$

$( {a}^{2} - 2ab + {b}^{2} )( - ab) = - {a}^{3} b + 2 {a}^{2} {b}^{2} - a {b}^{3}$

$( {x}^{5} - 6 {x}^{3} - 8x)(3 {a}^{2} {x}^{2} ) = 3 {a}^{2} {x}^{7} - 18 {a}^{2} {x}^{5} - 24 {a}^{2} {x}^{3}$

$( {m}^{4} - {m}^{2} {n}^{2} + 7 {n}^{4} ) (- 4 {m}^{3} x) = - 4 {m}^{7} x+ 4 {m}^{5} {n}^{2} x - 28 {m}^{3 } {n}^{4} x$

$( {x}^{3} - 4 {x}^{2} y + 6x {y}^{2} )(a {x}^{3} y) = a {x}^{6} y - 4 {x}^{5} {y}^{2} + 6a {x}^{4} {y}^{3}$