producto notable
a) ( 5 + b ) ( 25 - 5 a + a²)
b) ( x- 3 ) (x² + 3 x + 9 )
c) ( b + 3 ) ( b² - 2b + 4 )
d) ( 5 + 2 )³
e) ( c +3 ) ° ( c + 3 )²
f) ( 3 - c ) ³
ayuden por fa
angiemontenegr:
El primero es (5 + a) ?
Respuestas
Respuesta dada por:
2
Resolver.
Aplicas.
a³ + b³ = (a + b)(a² - ab + b²)
(5 + a)(25 - 5a + a²) =
(5 + a)(5² - 5a + a²)
5³ + a³
(b + 3)(b² - 3b + 9) =
(b+ 3)(b² - 3b + 3²) =
b³ + 3³
--------------------------------------------------------
Aplicas.
a³ - b³ = (a - b)(a² + ab + b²)
(x - 3)(x² + 3x + 9) =
(x - 3)(x² + 3x + 3²) =
(x³ - 3³)
-------------------------------------------------------------
Aplicas.
(a + b)³ = a³ + 3a²b + 3ab² + b³
(5 + 2)³ =
5³ + 3(5²)(2) + 3(5)(2²) + 2³ =
(5 * 5 * 5) + 3(25)(2) + 3(5)(4) + (2 * 2 * 2) =
125 + 150 + 60 + 8 =
343
-------------------------------------------------------------
Aplicas
aⁿ . aᵇ = aⁿ⁺ᵇ
(c + 3)⁰ (c + 3)²
(c + 3)⁰⁺² =
(c + 3)² = Aplicas producto notable (a + b)² = a² + 2ab + b²
c² + 2(c)(3) + 3² =
c² + 6c + 9
---------------------------------------------------------
Aplicas.
Producto notable.
(a - b)³ =
a³ - 3a²b + 3ab² - b³
(3 - c)³ =
3³ - 3(3²)(c) + 3(3)c² - c³ =
(3 * 3 * 3) - 3(9)c + 9c² - c³ =
27 - 27c + 9c² - c³
Aplicas.
a³ + b³ = (a + b)(a² - ab + b²)
(5 + a)(25 - 5a + a²) =
(5 + a)(5² - 5a + a²)
5³ + a³
(b + 3)(b² - 3b + 9) =
(b+ 3)(b² - 3b + 3²) =
b³ + 3³
--------------------------------------------------------
Aplicas.
a³ - b³ = (a - b)(a² + ab + b²)
(x - 3)(x² + 3x + 9) =
(x - 3)(x² + 3x + 3²) =
(x³ - 3³)
-------------------------------------------------------------
Aplicas.
(a + b)³ = a³ + 3a²b + 3ab² + b³
(5 + 2)³ =
5³ + 3(5²)(2) + 3(5)(2²) + 2³ =
(5 * 5 * 5) + 3(25)(2) + 3(5)(4) + (2 * 2 * 2) =
125 + 150 + 60 + 8 =
343
-------------------------------------------------------------
Aplicas
aⁿ . aᵇ = aⁿ⁺ᵇ
(c + 3)⁰ (c + 3)²
(c + 3)⁰⁺² =
(c + 3)² = Aplicas producto notable (a + b)² = a² + 2ab + b²
c² + 2(c)(3) + 3² =
c² + 6c + 9
---------------------------------------------------------
Aplicas.
Producto notable.
(a - b)³ =
a³ - 3a²b + 3ab² - b³
(3 - c)³ =
3³ - 3(3²)(c) + 3(3)c² - c³ =
(3 * 3 * 3) - 3(9)c + 9c² - c³ =
27 - 27c + 9c² - c³
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