Question

Hallar (x-3)/4-3=(x-20) /8

Answer 1

$\frac{(x-3)}{4-3} = \frac{(x-20)}{8}$

$8(x-3) = 4-3(x-20)$

$8x - 24 = 4 - 3x + 60$

$8x + 3x = 4 + 60 +24$

$11x = 88$

$x = \frac{88}{11}$

$x = 8$

SALUDOS! :D