Question

utilizando el metodo de igualacion , halla los volores x y y de los siguientes sistemas de ecuaciones 2 x 2 ayuda

Answer 1

Respuesta:

n

o.l

o

s

de

e

e

e

de

d

s

s

d

dd

d

d

d

d

d

d

d

d

Answer 2

Respuesta:

$8x = 30 + 15y \\ 2x = 15 - 3y \\ \times = 30 + 15 \div 8 \\ \times = 15 - 3y \div 2 \\ 15 - 3y \div 2 =30 + 15 \div 8 \\ {2}(30 + 15y) \\ {8}(15 - 3y) \\ 60 + 30y = 120 - 24y \\ 24y + 30y = 120 - 60 \\ 54y = 60$

$5x = - 4 + 7y \\ 9x = 40 - 11y \\ x = - 4 + 7y \div 5 \\ x = 40 - 11y \div 9 \\ 40 - 11y \div 9 = - 4 + 7y \div 5 \\ {5}(40 - 11y) \\ {9}( - 4 + 7y) \\ 200 - 55y = - 36 + 63y \\ 200 + 36 = 55y + 63y \\ 236 y= 118 \\ y = 2$

$7x = 27 + 3y \\ 5x = 0 + 6y \\ x = 27 + 3y \div 7 \\ x = 0 + 6y \div 5 \\ 0 + 6y \div 5 = 27 + 3y \div 7 \\ {5}(27 + 3y) \\ {7}(0 + 6y) \\ 135 + 15y = 0 \\ 15y = - 135 + 0 \\ y = - 135 \div 15 \\ y = - 27$

$5y = 1 - 2x \\ 7y = 3 - 6x \\ y = 1 - 2x \div 5 \\ y = 3 - 6x \div 7 \\ 1 - 2x \div 5 = 3 - 6x \div 7 \\ {5}(3 - 6x) \\ {7}(1 - 2x) \\ 15 - 30x = 7 - 14x \\ 15-7 = 30x- 14x \\ 8= 16x \\ x = 16 \div 8 \\ x =2$

$3y = 23 - 10x \\ 5y = 1 + 2x \\ y = 23 - 10x \div 3 \\ y = 1 + 2x \div 5 \\ 23 - 10x \div 3 = 1 + 2x \div 5 \\ {3}(1 + 2x) \\ {5}(23 - 10x) \\ 3 + 6x = 115 - 50x \\ 50x + 6x = 115 - 3 \\ 56x = 112 \\ x = 2$

$x = 100 - y \\ x = 12 y \\ 100 - y = 12 y \\ 100 - 12 = - 2y \\ y = 88 \div 2 \\ y = 44$