Question

ayudaaa

(x²4x+7) log5+log16=4​

Answer 1

$( x^2 4x + 7 ) log 5 + log 16 = 4\\x^2 * 4x + 7 * log 5 + log 16 = 4\\4x^3 + 4.89279 + log 16 = 4\\f ( x ) 4x^3 = 12x^2\\f ( x )12x^2 = 24x\\24x = 4.89279 + log 16 = 4\\24x = 4 - 4.89279 - log 16\\\\24x = - 2.09690\\x = - 2.09690 / 24\\ x = - 0.08737\\Demostracion :\\- 2.09690 + 4.89279 + log 16 = 4$