Question

Integrales por sustitución

Answer 1

$\int\limits \frac{dx}{\sqrt[3]{9x-1} }\\\\u=9x-1\\du=9dx\\\\\\\frac{1}{9} \int\limits \frac{9dx}{\sqrt[3]{9x-1} }\\\\\frac{1}{9} \int\limits \frac{du}{\sqrt[3]{u} }\\\\\frac{1}{9} \int\limits {u^{\frac{1}{3} } } \, du \\\\\frac{1}{9}(\frac{u^{\frac{1}{3}-1 } }{\frac{1}{3}-1} +c)\\\\\frac{1}{9} (\frac{u^{\frac{-2}{3} } }{\frac{-2}{3} } +c)\\\\\frac{1}{9}(\frac{-2}{3} .\frac{1}{u^{\frac{2}{3} } } +c)\\\\\frac{-2}{27\sqrt[3]{u^{2} } } +C\\\\\frac{-2}{27\sqrt[3]{(9x-1)^{2} } } +C$Respuesta:

Explicación: