Question

AYUDAAAAAAAAAA DOY LO QUE LES VENGA EN GANAS

Answer 1

Respuesta:

dame un momento brooooooooooo

Explicación paso a paso:

ahorita lo resuelvoooooooooo

Answer 2

Respuesta:

$\left(7m^4-3n^3\right)^2=49m^8-42m^4n^3+9n^6$

$\left(bc^5-11d^8\right)^2=b^2c^{10}-22bc^5d^8+121d^{16}$

$\left(6ab+2c\right)\left(6ab-2c\right)=36a^2b^2-4c^2$

$\left(5x^9-3y\right)\left(5x^9+3y\right)=25x^{18}-9y^2$

$\left(2b^5c^4+8d^6\right)\left(2b^5c^4-3y\right)=4b^{10}c^8-6b^5c^4y+16b^5c^4d^6-24d^6y$

Explicación paso a paso:$1) \left(7m^4-3n^3\right)^2\mathrm\\{Aplicar\:la\:formula\:del\:binomio\:al\:cuadrado}:\quad \left(a-b\right)^2=a^2-2ab+b^2\\a=7m^4,\:\:b=3n^3\\=\left(7m^4\right)^2-2\cdot \:7m^4\cdot \:3n^3+\left(3n^3\right)^2\\\\=49m^8-42m^4n^3+9n^6$$2) \left(bc^5-11d^8\right)^2\\\mathrm{Aplicar\:la\:formula\:del\:binomio\:al\:cuadrado}:\quad \left(a-b\right)^2=a^2-2ab+b^2\\a=bc^5,\:\:b=11d^8\\=\left(bc^5\right)^2-2bc^5\cdot \:11d^8+\left(11d^8\right)^2\\=b^2c^{10}-22bc^5d^8+121d^{16}$$3) \left(6ab+2c\right)\left(6ab-2c\right)\\\mathrm{Aplicar\:la\:siguiente\:regla\:para\:binomios\:al\:cuadrado:\:}\left(a+b\right)\left(a-b\right)=a^2-b^2\\a=6ab,\:b=2c\\=\left(6ab\right)^2-\left(2c\right)^2\\=36a^2b^2-4c^2$$4) \left(5x^9-3y\right)\left(5x^9+3y\right)\\\mathrm{Aplicar\:la\:siguiente\:regla\:para\:binomios\:al\:cuadrado:\:}\left(a-b\right)\left(a+b\right)=a^2-b^2\\a=5x^9,\:b=3y\\=\left(5x^9\right)^2-\left(3y\right)^2\\=25x^{18}-9y^2$$5) \left(2b^5c^4+8d^6\right)\left(2b^5c^4-3y\right)\\\mathrm{Aplicar\:la\:propiedad\:distributiva}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd\\a=2b^5c^4,\:b=8d^6,\:c=2b^5c^4,\:d=-3y\\=2b^5c^4\cdot \:2b^5c^4+2b^5c^4\left(-3y\right)+8d^6\cdot \:2b^5c^4+8d^6\left(-3y\right)\\\mathrm{Aplicar\:las\:reglas\:de\:los\:signos}\\+\left(-a\right)=-a\\=2\cdot \:2b^5b^5c^4c^4-2\cdot \:3b^5c^4y+8\cdot \:2b^5c^4d^6-8\cdot \:3d^6y\\=4b^{10}c^8-6b^5c^4y+16b^5c^4d^6-24d^6y$