Question

16x-[3x-(6-9x)]=30x+[-(3x+2-(x+3)]

Answer 1

16x-[3x-(6-9x)]=30x+[-(3x+2-(x+3))]
16x-[3x-6+9x]=30x+[-(3x+2-x-3)]
16x-[12x-6]=30x+[-(2x-1)]
16x-12x+6=30x+[-2x+1]
4x+6=30-2x+1
4x+6=31-2x
4x-2x=31-6
2x=25
x=25/2=12,5
Espero que te ayude