Question

10.Halle el mínimo común
múltiplo de
a. 126 y 92
b. 125 y 80
c. 90 y 126

Answer 1

Respuesta:

$a)126 = 2 \times {3}^{2} \times 7 \\ 92 = {2}^{2} \times 23 \\ M.C.M.(126,92) = {2}^{2} \times {3}^{2} \times 7 \times 23 = 4 \times 9 \times 7 \times 23 = 5796$

$b)125 = {5}^{3} \\ 80 = {2}^{4} \times 5 \\ M.C.M.(125,80 ) = {2}^{4} \times {5}^{3} = 16 \times 125 = 2000$

$c)90 = 2 \times {3}^{2} \times 5 \\ 126 = 2 \times {3}^{2} \times 7 \\ M.C.M.(90,126 ) = 2 \times {3}^{2} \times 5 \times 7 = 2 \times 9 \times 5 \times 7 = 630$