Question

Factorizar (x+y+z)³-x³-y³-z³
Factorizar 1+x(x+1)(x+2)(x+3)

Answer 1

1°- (x+y+z)³-x³-y³-z³
(x+y+z)³= x³+y³+z³ + 3(x+y)(x+z)(y+z)
x³+y³+z³ + 3(x+y)(x+z)(y+z) -x³-y³-z³ = 3(x+y)(x+z)(y+z)