Question

2.log4 (x-1) + log4 (x+4)= 2

Answer 1

(log(4))(x−1)+(log(4))(x+4)=2

Simplifica a:

1.20412x+1.80618=2

Vamos a resolver la ecuación paso a paso.

1.20412x+1.80618=2

Paso 1: Restar 1.80618 a ambos lados.

1.20412x+1.80618−1.80618=2−1.80618

1.20412x=0.19382

Paso 2: Dividir ambos lados por 1.20412.

1.20412x  =  0.19382

1.20412        1.20412

x = 0.160964

Solución:

x = 0.160964

-ThisXebuy

Answer 2

Respuesta:

$2\log4(x-1)+\log4(x+4)=2\\\log16(x-1)^2+\log(x+4)=2\\\log[16(x-1)^2*(x+4)]=2\\\log[16x^3+96x^2+144x+64]=2\\16x^3+96x^2+144x+64=100$

$16x^3+96x^2+144x-36=0$

$x=\sqrt[3]{4}+\dfrac{1}{\sqrt[2]{4}}-2$