Question

ayúdenme doy coronita​

Answer 1

Respuesta:

a) $(x+4)\cdot(x+10)=x^{2} +10x+4x+40=x^{2} +14x+40$

b) $(3x+4)\cdot(3x+1)=9x^{2} +3x+12x+4=9x^{2} +15x+4$

c) $(6x+10)\cdot(6x-2)=36x^{2} -12x+60x-20=36x^{2} +48x-20$