Question

Hallar el menor múltiplo de 11, que dividido por 2,3,4,5,6 y 7 da siempre de resto 1.

Answer 1

Answer:

We must have

k11 = 2a+ 1 , k11 = 3b+1, k11=4c+1,

k11 = 5d+1, k11 = 6e +1 , k11= 7f + 1 for some integers a,b,c,d,e,f. So, you must find k that simultaneously satisfies these conditions.