Question

Resuelve las siguientes multiplicaciones aplicando las leyes de los exponentes:
a) 10 (a+b+c)=
b) (2y) (5y + 3y -9)
c) (5n + 1) (2n-3)=
d) (5p + 3) (p^2-6p-5)=
e) (5pq^3 + 5p^2q^2- 4p^3q) (p^2 q^2- 2p^3q+ pq)=


Ayudaaaaa!!

Answer 1

Respuesta:

$a) 10(a + b + c) \\ 10a + 10b + 10c$

$b) (2y) (5y + 3y -9) \\ 10{y}^{2} + 6 {y}^{2} - 18y \\ 16 {y}^{2} - 18y$

$c)(5n + 1) (2n-3) \\ 10 {n}^{2} - 15n + 2n - 3 \\ 10 {n}^{2} - 13n - 3$

$d) (5p + 3) (p^2-6p-5) \\ 5 {p}^{3} - 30 {p}^{2} - 25p + 3 {p}^{2} - 18p - 15 \\ 5 {p}^{3} - 27 {p}^{2} - 43p - 15$

$e) (5pq^3 + 5p^2q^2- 4p^3q) (p^2 q^2- 2p^3q+ pq) \\ 5 {p}^{3} {q}^{5 } - 10 {p}^{4} {q}^{4} + 5 {p}^{2} {q}^{4} + 5 {p}^{4} {q}^{4} - 10 {p}^{5} {q}^{3} + 5 {p}^{3} {q}^{3} - 4 {p}^{5} {q}^{3} + 8 {p}^{6} {q}^{2} - 4 {p}^{4} {q}^{2} \\ 5 {p}^{3} {q}^{5} - 5 {p}^{4} {q}^{4} + 5 {p}^{2} {q}^{4} - 14 {p}^{5} {q}^{3} + 5 {p}^{3} {q}^{3} + 8 {p}^{6} {q}^{2} - 4 {p}^{4} {q}^{2}$