Question

Por favor ayudenme
3(4x-2)=-2x+3
(x+2)^2=(x+1)^2
X^2+2=0

x^2-x^2y
x^3-x^2+x+1
x^3-7x+2x^2 +14

Answer 1

3(4x-2)=-2x+3
12x-6=-2x+3
12x+2x=3+6
14x=9
x=9/14

$(x+2)^{2} = (x+1)^{2}$
$x^{2}+4x+4 = x^{2}+2x+1$
$x^{2} -x^{2}+4x-2x = 1-4$
2x = -3
x = -3/2