Question

Plis aiuda ;-; es de matematicas

Answer 1

$a) \sqrt{9+6} =\sqrt{15}$

$b) \sqrt[3]{64:8}=\sqrt[3]{2^{6}:2^{3} } =\sqrt[3]{2^{3} } =2$

$c) \sqrt{\sqrt{81} } =\sqrt[4]{3^{4} } =3$

$d) \sqrt[3]{27x64} =\sqrt[3]{3^{3}x2^{6} } =3x2^{2} =3x4=12$

$e) \sqrt{27} x\sqrt{3}=\sqrt{3^{3} } x\sqrt{3} =\sqrt{3^{4} } =3^{2} =9$

$f) \sqrt[5]{\sqrt{1} } =\sqrt[10]{1} =1$

$g) \sqrt{25-16} =\sqrt{9} =\sqrt{3^{2} } =3$

$h) \sqrt{4x121} =\sqrt{2^{2}x11^{2} } =2x11=22$

$i) \sqrt[3]{5152:64} =\sqrt[3]{2^{9}:2^{6} } =\sqrt[3]{2^{3} } =2$

$j) \sqrt{729} :\sqrt{81} =\sqrt{3^{6} } :\sqrt{3^{4} } =\sqrt{3^{6}:3^{4} } =\sqrt{3^{2} } =3$