Question

resuelve las siguientes operaciones combinadas con signos de agrupación.
me ayudas si porfa

Answer 1

$</p><p>Respuesta:</p><p>[tex]( \frac{7}{8} + \frac{4}{5} ) - ( \frac{9}{20} + \frac{ - 5}{2} ) \\ \frac{35 + 32}{40} - ( \frac{18 - 100}{40 } ) \\ \frac{67}{40} - ( \frac{ - 82}{40} ) = \frac{67}{40} + \frac{82}{40} \\ \frac{149}{40}$

$( \frac{ - 8}{15} - \frac{3}{4} ) + ( \frac{ - 9}{6} - \frac{ - 7}{10} ) \\ ( \frac{ - 32 - 45}{60} ) + ( \frac{ - 90 - ( - 42)}{60} ) \\ \frac{ - 77}{60} + \frac{ - 48}{60} = \frac{ - 125}{60} = \frac{ - 25}{12}$

$( \frac{ - 3}{2} - \frac{4}{5} ) + ( \frac{7}{3} + \frac{5}{2} ) \\ ( \frac{ - 15 - 8}{10} ) + ( \frac{14 + 15}{6} ) \\ \frac{ - 23}{10} + \frac{29}{6} = \frac{ - 138 + 290}{60} \\ \frac{152}{60} = \frac{38}{15}$

$( \frac{ - 6}{4} + \frac{3}{2} ) - ( \frac{6}{5} + \frac{4}{3} ) \\ \frac{ - 12 + 12}{8} - \frac{18 + 20}{15} \\ \frac{0}{8} - \frac{38}{15} = - \frac{38}{15}$

$( \frac{ - 9}{4} \times \frac{2}{5} ) + ( \frac{7}{10} \times \frac{4}{2} ) \\ \frac{ - 18}{20} + \frac{28}{20} = \frac{10}{20} = \frac{1}{2}$

$( \frac{ - 2}{5} \times \frac{7}{6} ) - ( \frac{4}{3} \times \frac{8}{1} ) \\ \frac{ - 14}{30} - \frac{32}{3} \times \frac{10}{10} = \frac{ - 14 - 320}{30} = \frac{ - 334}{30}$

[/tex]