Question

completar el trinomio cuadrado perfecto y encontra los valores de X1 y X2
X2-6x-7=0
X2-6x+ -7=0 X1=
X2-6x+ X2=

Answer 1

Respuesta:

Espero haberte ayudado ;)

Explicación paso a paso:

${x}^{2} - 6x + 7 = 0 \\ {x}^{2} - 6x + {3}^{2} + 7 = {3}^{2} \\ {(x - 3)}^{2} = 2 \\ x - 3 =± \sqrt{2} \\ x = ± \sqrt{2} + 3\\ x1 = 3 + \sqrt{2} \\ x2 = 3 - \sqrt{2}$

${x}^{2} -6x-7=0 \\ {x}^{2} - 6x + {3}^{2} - 7 = {3}^{2} \\{ (x - 3)}^{2} = 16 \\ x - 3 =±4 \\ x = 3±4 \\ x1 = 7 \\ x2 = - 1$

${x}^{2} - 6x + {x}^{2} = 0 \\ 2 {x}^{2} - 6x = 0 \\ {x}^{2} - 3x = 0 \\ {x}^{2} - 3x + {( \frac{3}{2} )}^{2} = {( \frac{3}{2} )}^{2} \\ {(x - \frac{3}{2}) }^{2} = {( \frac{3}{2} )}^{2} \\ x - \frac{3}{2} = ± \frac{3}{2} \\ x = \frac{3}{2} ± \frac{3}{2} \\ x1 = 3 \\ x2 = 0$