Question

productos conjugados
(3×+3)(3×-3)=

(4×+6y)(4×-6y)=

(4×+5)(4×-5)=

(7×+2y)(7×-2y)=

(4×+4y)(4×-4y)=

ayúdenme
​

Answer 1

Respuesta:

(3×+3)(3×-3)= (9x^2 - 9)

(4×+6y)(4×-6y)= (16x^2 - 36y^2)

(4×+5)(4×-5)= (16x^2 - 25)

(7×+2y)(7×-2y)= (49x^2 - 4y^2)

(4×+4y)(4×-4y)= (4x^2 - 4y^2)