Question

Alguien me puede resolver esto: (x+1)²=, (3+6)²=1, (4B+3C)²=, (56-36)²=, 2A-3B)²=, (5ABC-5BCD)²=​

Answer 1

(x+1)² = x² + 2x +1

(3+6)²  

(9)² = 81

(4B+3C)²    

16B² +24BC + 9C²

(56-36)²

(20)²

400

(2A - 3B)²

4A² -  12 AN + 9B²

Eternamente axllxa