Question

(x+1)^3-(x-1)^3=6x(x-3)

Answer 1

$\left(x+1\right)^3-\left(x-1\right)^3=6x\left(x-3\right)$
Expandimos y nos queda:
$6x^2+2=6x^2-18x$
Restamos 2 a cada lado:
$6x^2=6x^2-18x-2$
Restamos 6x^2 en ambos lados
$6x^2-\left(6x^2-18x\right)=6x^2-18x-2-\left(6x^2-18x\right)$
Nos queda que:
$x= \frac{2}{18} ; Decimal=0,11111$