• Asignatura: Matemáticas
  • Autor: milisanchez19
  • hace 6 años

me ayudann 1x²+58x+720=0 1x²+3x+2=0 1x²+5x+6=0 8x2+7x+2=0 8x²-10x+3=0 4x²-10x-6=0 3x²-4x+1=0​

Respuestas

Respuesta dada por: kurokuhasame
2

Respuesta:

voy a utilizar múltiples métodos para resolver estas ecuaciones.

Explicación paso a paso:

1.- x² + 58x + 720 = 0

x. 18 = 18x

x. 40 = 40x

= 58x

(x + 18)(x + 40) = 0

X1 = -18 y X2 = -40

2.- x² + 3x + 2 = 0

X1 + X2 = -3 y X1 × X2 = 2

(-3/2 + u)(-3/2 - u) = 2

9/4 - 2 = u²

1/4 = u²

√(1/4) = 1/2 = u

X1 = -3/2 + 1/2 = -2/2 = -1

X2 = -3/2 - 1/2 = -4/2 = -2

3.- x² + 5x + 6 = 0

x. 3 = 3x

x. 2 = 2x

= 5x

(x + 3)(x + 2) = 0

X1 = -3 y X2 = -2

4.- 8x² + 7x + 2 = 0

X1 + X2 = -7/8 y X1 × X2 = 1/4

(-7/16 + u)(-7/16 - u) = 1/4

49/256 - 1/4 = u²

√( -15/256) = u

X1 = -7/16 + √(-15)/16 = [-7 + √(-15)]/16

X2 = -7/16 - √(-15)/16 = [-7 - √(-15)]/16

5.- 8x² - 10x + 3 = 0

∆ = (-10)² - 4(3)(8)

∆ = 100 - 96

∆ = 4

x = [b (+,-) √∆]/2a

x = [10 (+,-) √4]/16

X1 = [10 + 2]/16 = 12/16 = 3/4

X2 = [10 - 2]/16 = 8/16 = 1/2

4.- 4x² - 10x - 6 = 0

∆ = (-10)² - 4(-6)(4)

∆ = 100 + 96

∆ = 196

x = [b (+, -) √∆]/2a

x = [10 (+,-) √196]/8

X1 = (10 + 14)/8 = 24/8 = 3

X2 = (10 - 14)/8 = -4/8 = -1/2

5.- 3x² - 4x + 1 = 0

3x. -1 = -1x

x. -1 = -3x

= -4x

(3x - 1)(x - 1) = 0

X1 = 1/3 y X2 = 1

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