Question

ayuda ayuda ayuda ayuda ayuda ayuda, es urgente x'D

Answer 1

Respuesta:

segun el planteamiento la respuesta es la opcion C, saludos.

Answer 2

Respuesta:

꧁Holi꧂

$(x + 4 {)}^{2} + (x + 1 {)}^{2} + 2x = (x + 6 {)}^{2} + (x - 1 {)}^{2}$

${x}^{2} + 8x + 16 + (x + 1 {)}^{2} + 2x = (x + 6 {)}^{2} + (x - 1 {)}^{2}$

${x}^{2} + 8x + 16 + {x}^{2} + 2x + 1 + 2x = (x + 6 {)}^{2} + (x - 1 {)}^{2}$

${x}^{2} + 8x + 16 + {x}^{2} + 2x + 1 + 2x = {x}^{2} + 12x + 36 + (x - 1 {)}^{2}$

${x}^{2} + 8x + 16 + {x}^{2} + 2x + 1 + 2x = {x}^{2} + 12x + 36 + {x}^{2} - 2x + 1$

${x}^{2} + 8x + 16 + 2x + 1 + 2x = {x}^{2} + 12x + 36 - 2x + 1$

$8x + 16 + 2x + 1 + 2x = 12x + 36 - 2x + 1$

$8x + 16 + 2x + 2x = 12x + 36 - 2x$

$12x + 16 = 12x + 36 - 2x$

$12x + 16 = 10x + 36$

$12 x- 10x + 16 = 36$

$12x - 10x = 36 - 16$

$2x = 36 - 16$

$2x = 20$

$x = 10$

Rpt: 10