Question

Si a²+6² = 13 ya-b = 1, calcule ab​

Answer 1

Hola!

Respuesta:

$ab = 6$

Explicación paso a paso:

∆) Solución:

$a - b = 1 \\ {(a - b)}^{2} = {(1)}^{2} \\ {a}^{2} - 2ab + {b}^{2} = 1 \\ {a}^{2} + {b}^{2} - 2ab = 1 \\( {a}^{2} + {b}^{2} ) - 2ab = 1 \\ (13) - 2ab = 1 \\ 13 - 1 = 2ab \\ 12 = 2ab \\ \frac{12}{2} = ab \\ ab = 6$