Question

cuales el procedimiento de (secB+tanB)(1-senB)=1

Answer 1

Realizar transformaciones con identidades trigonométricas:

$\[\left( {\sec \left( \beta \right) + \tan \left( \beta \right)} \right)\left( {1 - \sin \left( \beta \right)} \right) = 1\]$

$\[\left( {\frac{1}{{\cos \left( \beta \right)}} + \frac{{\sin \left( \beta \right)}}{{\cos \left( \beta \right)}}} \right)\left( {1 - \sin \left( \beta \right)} \right) = 1\]$

$\[\frac{1}{{\cos \left( \beta \right)}}\left( {1 + \sin \left( \beta \right)} \right)\left( {1 - \sin \left( \beta \right)} \right) = 1\]$

$\[\frac{1}{{\cos \left( \beta \right)}}\left( {1 - \sin {{\left( \beta \right)}^2}} \right) = 1\]$

$\[\frac{{\cos {{\left( \beta \right)}^2}}}{{\cos \left( \beta \right)}} = 1\]$

$\[\cos \left( \beta \right) = 1\]$

El angulo que satisface es:

$\[\beta = arc\cos \left( 1 \right)\]$

Finalmente:

$\[\beta = 0\]$