Question

[tex] (x-5)^{2} = x(x-8)+11

Answer 1

desarrollando los factores
$x^{2} -10x+25= x^{2} -8x+11$
pasando todo a la izq.
$x^{2} - x^{2} -10x+8x+25-11=0$
$-2x+14=0$
$x= \frac{14}{2} =7$