Question

resuelve: x²-6x+1=0 e indica una de sus raíces​

Answer 1

Respuesta:

$x^{2} -6x+1=0$

$x=\frac{-(-6)+\sqrt{(-6)^{2} -4(1)*(1)} }{2*(1)} =\frac{-(-6)-\sqrt{(-6)^{2} -4(1)*(1)} }{2*(1)}$

$x=\frac{6+\sqrt{36-4} }{2} =\frac{6-\sqrt{36-4} }{2}$

$x=\frac{6+\sqrt{32} }{2}= \frac{6-\sqrt{32} }{2}$

$x=\frac{6+4\sqrt{2} }{2}=\frac{6-4\sqrt{2} }{2}$

$x=3+2\sqrt{2}=3-2\sqrt{2}$

x=5.828=0.17157