Question

xfavor ayudeme resolviendo
x + y + z = 3
6z - 2x = 0
x + y - z=0

Answer 1

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$6z - 2x = 0 \\ 6z = 2x \\ \frac{z}{x} = \frac{k}{3k}$

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$x + y + z = 3 \\ 3k + y + k = 3 \\ 4k + y = 3$

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$x + y - z = 0 \\ 3k + y - k = 0 \\ 2k + y = 0$

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$4k - 2k + y - y = 3 - 0 \\ 2k = 3 \\ k = \frac{3}{2}$

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$2( \frac{3}{2} ) + y = 0 \\ y = - 3$

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$x = 3k \\ x = 3 \times \frac{3}{2} \\ x = \frac{9}{2}$

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$z = k \\ z = \frac{3}{2}$