Question

determine la formula molecular para la estrona (una hormona sexual femenina) cuya composicion centesimal es: C=80% H=8,2% O=11,8% la masa molecular de la estrona es 270 g/mol

dejen procedimiento
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Answer 1

Mm C: 12 g/mol
        H: 1 g/mol
        O: 16 g/mol

C: 80 g / 12 g/mol = 6.667 mol
H: 8.2 g / 1 g/mol = 8.2 mol
O: 11.8 g / 16 g/mol = 0.738 mol

dividir cada elemento entre el menor numero

C: 6.667 mol / 0.738 mol =9
H: 8.2 mol / 0.738 mol = 11
O: 0.738 mol / 0.738 mol = 1

FE: C9H11O1

Mm FE
C: 9 x 12 = 108 g/mol
H: 11 x 1 = 11 g/mol
O: 1 x 16 = 16 g/mol
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        Mm = 135 g/mol

n = 270 g/mol / 135 g/mol
n = 2

FM = (FE)n

FM = (C9H11O1)2

FM = C18 H22O2