Question

q alguien me explique por favor:c​

Answer 1

Respuesta:

$\frac{1 - 2x}{ 3 - x} + x = \frac{1}{x + 2} \\ \frac{1 - 2x + (3 - x)(x) }{3 - x} = \frac{1}{x + 2 } \\ \frac{1 - 2x + 3x - {x}^{2} }{3 - x} = \frac{1}{x + 2} \\ 1 + x - {x}^{2} (x + 2) = 3 - x \\ 1 + x - {x}^{3} - 2 {x}^{2} = 3 - x \\ 2x - {x}^{3} - 2 {x}^{2} = 2$