Question

Log9 (x+1)+log9 (9x+9)=2

pd: los 9 son la base

Answer 1

$log _{9} (x+1)+log _{9}(9x+9)=2$
$]log _{9}((x+1)(9x+9))=2$
$log _{9} (9 x^{2} +18x+9)=2$
$9 x^{2} +18x+9=9 ^{2}$