Question

resuelve y comprueba las siguientes
cuadráticas puras
ecuaciones
${6x}^{2} - 24 = 0$
${2x}^{2} - 50 = 0$
${ - 4x}^{2} + 36 = 0$
${3x}^{2} - 16 = 0$
${4x}^{2} - 16 = 0$
​

Answer 1

Respuesta:

$6 x^{2} - 24= 0\\6x^{2} = 24\\x^{2} = \frac{24}{6} \\\x^{2} = 4\\\sqrt{x^{2} } = \sqrt{4} \\x= + 2\\x= -2$

$2 x^{2} - 50= 0\\2x^{2} = 50\\\x^{2} = \frac{50}{2} x^{2} = 25\\\sqrt{x^{2} } =\sqrt{25} \\x= +5\\x= -5$

$-4 x^{2} + 36= 0\\-4 x^{2} = -36\\\\x^{2} = \frac{-36}{-4} \\x^{2} = 9\\\sqrt{x^{2} } = \sqrt{9} \\x= +9\\x= -9$

$3 x^{2} -16= 0 \\x= +/-\frac{0\sqrt{0-4 (3)(-16)} }{2(3)} \\x= +/-\frac{\sqrt{192} }{6} \\x= +/- \frac{13.85}{6} \\x= + 2.31\\x= - 2.31$

$4 x^{2} -16= 0\\4x^{2} = 16\\x^{2}= \frac{16}{4}\\x^{2} = 4\\\sqrt{x^{2} }= \sqrt{4} \\x= +2\\x=-2$

Espero te sea de ayuda!!