Question

Porfa necesito ayuda ​

Answer 1

Respuesta:

$11x-5\left(2x+\frac{1}{2}\right)=\frac{3}{5}\left(x-\frac{1}{2}\right)-1$

$11x-10x-\frac{5}{2}=\frac{3}{5}\left(x-\frac{1}{2}\right)-1\\\\\mathrm{Sumar\:elementos\:similares:}\:11x-10x\\\\x-\frac{5}{2}=\frac{3}{5}\left(x-\frac{1}{2}\right)-1$

$x-\frac{5}{2}=-\frac{13}{10}+\frac{3}{5}x\\\\\mathrm{Sumar\:}\frac{5}{2}\mathrm{\:a\:ambos\:lados}\\\\x-\frac{5}{2}+\frac{5}{2}=-\frac{13}{10}+\frac{3}{5}x+\frac{5}{2}$

$x=\frac{3\left(x+2\right)}{5}\\\\\mathrm{Multiplicar\:ambos\:lados\:por\:}5\\\\x\cdot \:5=\frac{3\left(x+2\right)}{5}\cdot \:5\\\\5x=3\left(x+2\right)$

$5x=3x+6\\\\\mathrm{Restar\:}3x\mathrm{\:de\:ambos\:lados}\\\\5x-3x=3x+6-3x\\\\2x=6\\\\x=\frac{6}{2} \\\\x=3$