Question

x²+2x-15=0

a ²-6 a + 8 = 0

f²- 3 f = 4

j ² =3x + 4

me podrán ayudar a resolver estas ecuaciones por favor
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Answer 1

Explicación paso a paso:

$1)x {}^{2} + 2x - 15 = 0 \\ (x + 5)(x - 3) = 0 \\ x = - 5 \\ x = 3 \\ 2)a {}^{2} - 6a + 8 = 0 \\ (a - 2)(a - 4) = 0 \\ a = 2 \\ a = 4 \\ 3)f²- 3 f - 4 = 0 \\ (f - 4)(f + 1) = 0 \\ f = 4 \\ f = - 1 \\ 4)j ² - 3x - 4 = 0 \\ (j -4)(j - + 1) = 0 \\ j = 4 \\ j = - 1$