Question

1.-7x² + 21x − 28 = 0
2.-−x² + 4x − 7 = 0
3.-12x² − 3x = 0

Answer 1

Respuesta:

Explicación paso a jscnldñpaso:

3kfstoñgvlfglflLGLftsñ

Answer 2

CALCULAR 1,2y3:

$1.-7x² + 21x − 28 = 0\\\\x^{2} + 3 - 4 = 0\\\\x^{2} =\frac{-3+\sqrt{9+16} }{2} = \frac{-3+5}{2} ----> X1 = 1 ; X2 = -4\\\\2. -x^{2} + 4x -7 = 0\\x = \frac{4+\sqrt[n]{16-28} }{2} = \frac{-3+\sqrt{-12} }{2}\\ x^{2} - 4x + 4 = 0\\x = \frac{4+\sqrt{16-16} }{2} = \frac{4+0}{2} = 2\\ \\3.-12x^{2} -3x = 0\\4x^{2} - x = 0\\x(4-1) = 0\\x= 0\\4x - 1 = 0 x = 1/4$