Question

con solución porfavor .....!!

Answer 1

Respuesta:

$\frac{a}{b} = \frac{2k}{3k} \\ (2k) {}^{2} + (3k) {}^{2} = 52 \\ 4k {}^{2} + 9k {}^{2} = 52 \\ k {}^{2} (4 + 9) = 52 \\ k {}^{2} = 4 \\ k = 2 \\ \\ hallar \: b - a \\ 3k - 2k = k = 2$