Question

los resuelven por favor doy coronita ,pero me urgen ​

Answer 1

a) 2x(3x + 4) = $x^{2}$ - x

$5x^{2}$ + 6x =  $x^{2}$ - x

$5x^{2}$ - $x^{2}$ + 6x + x = 0

4$x^{2}$ + 7x = 0

b) 4$x^{2}$ - 6x -2 = -2$x^{2}$ - 6x + 2

4$x^{2}$  + 2$x^{2}$  -6x +6x -2 -2 = 0

6$x^{2}$ - 4 = 0

c) 3($x^{2}$  + 2x) - 8 = 2x(x -2) - 9

3$x^{2}$  + 6x -8 = 2$x^{2}$  - 4x - 9

3$x^{2}$  - 2$x^{2}$  + 6x -4x = -9 + 8

$x^{2}$ + 2x = -1

$x^{2}$ + 2x + 1 = 0

d) 3 - 7$x^{2}$  + 8x = 7x - 6$x^{2}$  + 3

-7$x^{2}$  + 6$x^{2}$  + 8x - 7x = +3 -3

-$x^{2}$   + x = 0