Question

Calcula el area de un rombo donde sus diagonales sumen 30 y la diagonal mayor mide 6 cm mas que la diagonal menor
AYUDENME plisss

Answer 1

Respuesta:

       $108 cm^{2}$

Explicación paso a paso:

Diagonal menor:  d

Diagonal mayor:  D = d + 6 cm

Diagonal mayor + Diagonal menor = 30 cm

( d + 6 cm ) + ( d ) = 30 cm

d + 6 cm + d = 30 cm

d + d + 6 cm = 30 cm

2d = 30 cm - 6 cm

2d = 24 cm

d = 24 cm / 2

d = 12 cm

Diagonal menor: d = 12 cm

Diagonal mayor: D = d + 6 cm = 12 cm + 6 cm = 18 cm

Área del rombo:

$A = \frac{D * d }{2} = \frac{18cm *12cm}{2} = \frac{216 cm^{2} }{2}$

$A = 108 cm^{2}$