Question

∫( 21x^4+24x^5+20x^3+18x^3+10x)dx

Answer 1

Respuesta:

$\frac{21x^5}{5}+ 4x^6+\frac{38x^4}{4}+5x^2$

Explicación:

$\int\limit {(21x^4+24x^5+20x^3+18x^3+10x)dx} =\\\int\limit {21x^4dx}+\int\limit {24x^5dx}+\int\limit {20x^3dx}+\int\limit {18x^3dx}+\int\limit {10xdx}=\\\frac{21x^5}{5}+ \frac{24x^6}{6}+\frac{20x^4}{4}+\frac{18x^4}{4}+\frac{10x^2}{2}=\\\frac{21x^5}{5}+ 4x^6+\frac{38x^4}{4}+5x^2$