Question

Reparte 480 en partes inversamente proporcionales a 3 y 5

Answer 1

IP a 3 y 5
1) 1/3 x k
2) 1/5 x k
MCM  de 3 y 5 = 15
1) 1/3 x 15 = 5k
2) 1/5 x 15 = 3k
5k + 3k = 480
8k = 480
k = 60
1) 5k =5 x60 = 300
2) 3k = 3x 60 = 180