Question

Demostrar PASO A PASO$\frac{tan2x+sen2x}{cos^2 \alpha } = \frac{tan2x-sen2x}{sen^2 \alpha }$Una manito, Gracias

Answer 1

(tan2x + sen2x)/cos²x

= tan2x (1+(sen2x/tan2x)) / cos²x

= tan2x (1+cos2x) / (sen²x/tan²x)

= tan2x (2cos²x)(tan²x) / sen²x

= tan2x (2sen²x) / sen²x

= tan2x (1 - cos2x) / sen²x

= (tan2x - tan2x cos2x) / sen²x

= (tan2x - sen2x) / sen²x

L.Q.Q.D