Question

resuelve las siguientes ecuaciones​

Answer 1

Respuesta:

$a.\:\:\:\: x+\dfrac{2}{6} = \dfrac{1}{2}$

$x+\dfrac{1}{3} = \dfrac{1}{2}$

$x = \dfrac{1}{2} - \dfrac{1}{3}$

$x = \dfrac{3}{6} - \dfrac{2}{6}$

$x = \dfrac{3-2}{6}$

$\boxed{x=\dfrac{1}{6} }$

$b.\:\:\:\:\:\: \dfrac{5}{3} = \dfrac{3}{7} +y$

$\dfrac{3}{7} +y=\dfrac{5}{3}$

$y=\dfrac{5}{3} - \dfrac{3}{7}$  

$y=\dfrac{35}{21} - \dfrac{9}{21}$

$y=\dfrac{35-9}{21}$

$\boxed{y=\dfrac{26}{21}}$

$c.\:\:\:\:\:\:\dfrac{2}{8} \:\:+\:\: \dfrac{1}{4} = \dfrac{1}{2}\:\: -\:\: z$

$\dfrac{2}{8} \:\:+\:\: \dfrac{1}{4}\:\:+\:\:z = \dfrac{1}{2}$

$\dfrac{1}{2} + z =\dfrac{1}{2}$

$z =\dfrac{1}{2} - \dfrac{1}{2}$

$\boxed{z =0}$

$d.\:\:\:\:\:m-\dfrac{1}{7} =\dfrac{3}{5}$

$m =\dfrac{3}{5} + \dfrac{1}{7}$

$m =\dfrac{21}{35} + \dfrac{5}{35}$

$m =\dfrac{21+5}{35}$

$\boxed{m =\dfrac{26}{35}}$