Question

solucion?
(tan x / sen x) + csc x × cot x= sec x × csc² x​

Answer 1

Respuesta:

Explicación paso a paso:

       $\frac{tan~x}{sen~x}+csc~x*cot~x=sec~x*csc^2~x\\\\\frac{\frac{sen~x}{cos~x}}{sen~x}+(\frac{1}{sen~x}*\frac{cos~x}{sen~x})=sec~x*csc^2~x\\\\\frac{sen~x}{sen~x*cos~x}+\frac{cos~x}{sen^2~x}=sec~x*csc^2~x\\\\\frac{1}{cos~x}+\frac{cos~x}{sen^2~x}=sec~x*csc^2~x\\\\\frac{sen^2~x~+~(cos~x~*~cos~x)}{cos~x~*~sen^2~x}=sec~x*csc^2~x\\\\\frac{sen^2~x~+~cos^2~x}{cos~x~*~sen^2~x}=sec~x*csc^2~x\\\\\frac{1}{cos~x~*~sen^2~x}=sec~x*csc^2~x$

      $\frac{1}{cos~x}*\frac{1}{sen^2~x}=sec~x*csc^2~x\\\\sec~x*csc^2~x=sec~x*csc^2~x$