Question

1.-Calcular “2x – 11” si:
Tan (x + 30°) = ctg (5x + 30°)

2.-Hallar “x – 4” de:
Tan$Tan(\frac{7x+1°}{2} ) Ctg (\frac{2x+27}{3} ) = 1$

Answer 1

Respuesta:

Explicación paso a paso:

1.-

Calcular “2x – 11” si:

Tan (x + 30°) = ctg (5x + 30°)

x + 30 +  5x + 30  = 90

resolvemos

6x + 60 = 90

6x = 90 - 60

6x = 30

x = 30/6

x = 5

--

piden 2x – 11

2.(5) - 11

10 - 11

-1

--

2 )  hallar x - 4 de :

$tan\dfrac{7x+1}{2} .ctg\dfrac{2x+27}{3} = 1$

resolvemos

$tan\dfrac{7x+1}{2} = \dfrac{1}{ctg\dfrac{2x+27}{3}}$

$tan\dfrac{7x+1}{2} = tan\dfrac{2x+27}{3}$

igualamos

$\dfrac{7x+1}{2} = \dfrac{2x+27}{3}$

resolvemos

3(7x + 1) = 2(2x +27)

21x + 3 = 4x + 54

21x - 4x = 54 - 3

17x = 51

x = 51/17

x = 3

--

piden x - 4

3 - 4

-1