Question

Ayúdenme!! porfa!!

2x+6/4 + 6x-5/8 = 3x+7/3

Answer 1

Hola!

$2x+\frac{6}{4}+6x-\frac{5}{8}=\frac{3x+7}{3}\quad :\quad x=\frac{5}{24}\quad \left(\mathrm{Decimal}:\quad x=0.20833\dots \right)$

$2x+\frac{6}{4}+6x-\frac{5}{8}=\frac{3x+7}{3}$

$2x+6x+\frac{6}{4}-\frac{5}{8}=\frac{3x+7}{3}$

$8x+\frac{6}{4}-\frac{5}{8}=\frac{3x+7}{3}$

$8x+\frac{3}{2}-\frac{5}{8}=\frac{3x+7}{3}$

$\frac{12}{8}-\frac{5}{8}=\frac{3x+7}{3}$

$\frac{12-5}{8}=\frac{3x+7}{3}$

$8x+\frac{7}{8}=\frac{3x+7}{3}$

$8x\cdot \:3+\frac{7}{8}\cdot \:3=\frac{3x+7}{3}\cdot \:3$

$24x+\frac{21}{8}=3x+7$

$24x+\frac{21}{8}-\frac{21}{8}=3x+7-\frac{21}{8}$

$24x=3x+\frac{35}{8}$

$24x-3x=3x+\frac{35}{8}-3x$

$21x=\frac{35}{8}$

$\frac{21x}{21}=\frac{\frac{35}{8}}{21}$

$x=\frac{5}{24}$

ATTE CLAVIJO