Question

Porfa ayuda tienen q poner tambien como lo resolvieron

Answer 1

a) (2/3)^2÷(8/15)+√(25/81)×(1/10)

= (2^2/3^2)÷(8/15)+[(√25)/(√81)]×(1/10)

=(4/9)÷(8/15)+(5/9)×(1/10)

=(4×15)/(9×8)+(5×1)/(9×10)

=60/72+5/90

=5/6+1/18=(5×3+1)/18=16/18=8/9

= 8/9

b) 3√(1/2-3/8)+(1-2/5)÷0,1

= 3√((4×1-3)/8)+(5×1-2)/5÷(1/10)

= 3√(1/8)+(3/5)÷(1/10)

= (1/2) + (3×10)/(5×1)

= (1/2) + 30/5

= 1/2 + 6= (1+2×6)/2=13/2

=13/2 = 6,5

c) 3√0,125=3√(125/1000)=3√125/3√1000

= 5/10=1/2=0,5

d) (3/2)^3÷(15/4)-(8/5)×(1-3/4)

= (3^3/2^3)÷(15/4)-(8/5)×(1/4)

=(27/8)÷(15/4)-(8×1)/(5×4)

=(27×4)/(8×15)-8/20

=9/10-4/10=(9-4)/10=5/10=1/2=0,5

e) √1,44×√0,01+(0,23×10-1,7)^2

= √(144/100)×√(1/100)+(2,3-1,7)^2

= (√144/√100)×(√1/√100)+(0,5)^2

= (12/10)×(1/10)+(1/2)^2=12+1/4

=12/100+0,25=0,12+0,25=0,37

f) 2,5÷5×0,2+√(0,08×2+0,2)×(1,3)^2

=(5/2)÷(5/1)×(2/10)+√(0,16+0,2)×1,69

=(5×1×2)/(2×5×10)+√0,36×1,69

= 10/100+0,6×1,69

= 1/10+1,014=0,1+1,014=1,114

a) (1/3)^2+(1/3)^3. <. 1

= 1/9+1/27

= 3/27+1/27

= 4/27. <. 27/27

b) 0,2^2+0,5×3. >. 2×0,001

= 0,04+1,5. 0,002

= 1,54. >. 0,002

c) 0,3^3×0,1^2+√(1/100). < (4,35-3,2)^2

= 0,027×0,01+√1/√100. <. (1,05)^2

= 0,00027+1/10. < 1,1025

= 0,00027+0,1. < 1,1025

= 0,10027. <. 1,1025

d) (5/4)^2+√(49/16) >. 0,2^3÷0,2^2

=(1,25)^2+7/4. >. 0,2^(3-2)

= 1,5625+1,75. >. 0,2^1

= 3,3125. >. 0,2

e) 0,55+0,24×4. > 3√(27/8)-5/6

=0,55+0,96. > 3/2-5/6

= 1,51. >. 9/6-5/6=4/6=2/3=0,667

= 1,51. >. 0,67

f)

√(2-1/25)÷0,5 > (1,3^2-0,4^3)×0,1

=√(49/25)÷(1/2) >. (1,69-0,064)×(1/10)

=(7/5)÷(1/2). >. 1,626×(1/10)

=14/5. > 0,1626

= 2,8. >. 0,1626