Question

integral definida de 7 a 2
$2 \sqrt{xdx}$
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Answer 1

Respuesta:

$\int\limits_2^7 2\sqrt{x} \, dx =2\int\limits_2^7 \sqrt{x} \, dx=2\int\limits_2^7 x^{1/2} \, dx=2\left[\frac{x^{3/2}}{3/2}\right]_2^7=2\left[\frac{7^{3/2}}{3/2}-\frac{2^{3/2}}{3/2}\right]=$

$2\left[\frac{7^{3/2}-2^{3/2}}{3/2}}\right]=\frac{4(7\sqrt{7}-2\sqrt{2}) }{3}$