Question

cot x + tan x = sec x * csc x

Answer 1

$cotx+tanx=secx.cscx \\ \\ \frac{cosx}{senx}+\frac{senx}{cosx}=\frac{1}{cosx}.\frac{1}{senx} \\ \\ \frac{cos^2x+sen^2x}{senxcosx}=\frac{1}{senx.cosx} \\ \\ \boxed{\frac{1}{senxcosx}=\frac{1}{senxcosx} } \ \ \ cqd$